Moments, Skewness and Kurtosis
Skewness: which way the distribution leans
A distribution is symmetric when its two halves mirror each other; then mean = median = mode. If the right tail is longer it is positively skewed and mean > median > mode; if the left tail is longer it is negatively skewed and mean < median < mode. Income distributions are the classic positive case: a few very high incomes drag the mean up.
| Measure | Formula | Limits |
|---|---|---|
| Karl Pearson (first) | (Mean − Mode) ÷ σ | usually −3 to +3 |
| Karl Pearson (second) | 3(Mean − Median) ÷ σ | −3 to +3 |
| Bowley (quartile) | (Q₃ + Q₁ − 2Q₂) ÷ (Q₃ − Q₁) | −1 to +1 |
| Kelly (percentile) | (P₉₀ + P₁₀ − 2P₅₀) ÷ (P₉₀ − P₁₀) | −1 to +1 |
| Moment | β₁ = μ₃² ÷ μ₂³, γ₁ = μ₃ ÷ σ³ | β₁ ≥ 0; γ₁ carries the sign |
Worked: mean 50, mode 45, σ = 10 gives Pearson's Sk = (50 − 45)/10 = 0.5, a moderate positive skew. With Q₁ = 20, Q₂ = 30, Q₃ = 50, Bowley's Sk = (50 + 20 − 60)/(50 − 20) = 10/30 ≈ 0.33: the upper quartile is farther from the median than the lower one.
Kurtosis: how peaked the distribution is
Kurtosis compares the peak and tails of a distribution with the normal curve. Its moment measure is β₂ = μ₄ ÷ μ₂², with γ₂ = β₂ − 3 (excess kurtosis). The normal curve has β₂ = 3 and is mesokurtic; β₂ > 3 is leptokurtic (tall, thin peak and heavy tails); β₂ < 3 is platykurtic (flat-topped). In the worked example β₂ = 27/3² = 3, so that distribution is mesokurtic, and μ₃ = 0 makes it symmetric.
A quantile measure also exists: the percentile coefficient of kurtosis κ = Q.D. ÷ (P₉₀ − P₁₀), which is about 0.263 for a normal distribution.
Exam traps and a quick revision
- μ₁ = 0 and μ₂ = σ² always; μ₂ = μ′₂ − μ′₁².
- Positive skew: mean > median > mode; negative skew: the reverse.
- Bowley's and Kelly's coefficients lie between −1 and +1; Bowley ignores the outer quarters.
- β₂ = 3 mesokurtic, > 3 leptokurtic, < 3 platykurtic.
- For any distribution β₂ ≥ β₁ + 1, so β₂ is never less than 1.
Key takeaways
- Central moments are moments about the mean: μ₁ = 0, μ₂ = variance.
- μ₃ = μ′₃ − 3μ′₂μ′₁ + 2μ′₁³ and μ₄ = μ′₄ − 4μ′₃μ′₁ + 6μ′₂μ′₁² − 3μ′₁⁴.
- Pearson Sk = (Mean − Mode)/σ ≈ 3(Mean − Median)/σ; Bowley Sk = (Q₃ + Q₁ − 2Q₂)/(Q₃ − Q₁).
- β₁ = μ₃²/μ₂³ measures the size of skew; the sign comes from μ₃.
- β₂ = μ₄/μ₂²: 3 for the normal curve; above 3 leptokurtic, below 3 platykurtic.
Practice questions (10)
Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.
A distribution with β₂ = 3 is called:
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Answer: B — mesokurtic
β₂ = 3 is the kurtosis of the normal curve, the reference level called mesokurtic. Kurtosis says nothing about skewness, which needs μ₃.In a positively skewed distribution:
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Answer: A — mean > median > mode
The long right tail pulls the mean furthest to the right, the median follows part of the way, and the mode stays at the peak.The second central moment μ₂ of a distribution is its:
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Answer: A — variance
μ₂ = Σf(x − x̄)²/N, which is the variance by definition. The SD is its square root, and the first central moment is always zero.The first two moments of a distribution about the value 5 are 2 and 20. The variance is:
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Answer: C — 16
μ₂ = μ′₂ − μ′₁² = 20 − 4 = 16. The mean is A + μ′₁ = 7, which is not needed for the variance.About a point A the first four moments are 1, 4, 10 and 46. The fourth central moment μ₄ is:
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Answer: C — 27
μ₄ = μ′₄ − 4μ′₃μ′₁ + 6μ′₂μ′₁² − 3μ′₁⁴ = 46 − 40 + 24 − 3 = 27. With μ₂ = 3, β₂ = 27/9 = 3, so the distribution is mesokurtic.A distribution has mean 50, mode 45 and standard deviation 10. Karl Pearson's coefficient of skewness is:
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Answer: A — 0.5
Sk = (Mean − Mode)/σ = (50 − 45)/10 = 0.5. It is positive because the mean exceeds the mode.For a distribution Q₁ = 20, median = 30 and Q₃ = 50. Bowley's coefficient of skewness is:
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Answer: C — 1/3
Sk = (Q₃ + Q₁ − 2Q₂)/(Q₃ − Q₁) = (50 + 20 − 60)/30 = 10/30 = 1/3. Q₃ is farther from the median than Q₁, so the skew is positive.Bowley's coefficient of skewness always lies between:
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Answer: B — −1 and +1
Because Q₃ + Q₁ − 2Q₂ can never exceed Q₃ − Q₁ in size, Bowley's measure is bounded by ±1. Pearson's measure is the one usually quoted as lying within ±3.A distribution has mean 60, median 57 and standard deviation 9. Its coefficient of skewness based on the median is:
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Answer: A — 1
Pearson's second coefficient = 3(Mean − Median)/σ = 3 × 3/9 = 1. Forgetting the factor 3 gives 1/3.For a distribution μ₂ = 4 and μ₄ = 60. The distribution is:
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Answer: D — leptokurtic, since β₂ = 3.75
β₂ = μ₄/μ₂² = 60/16 = 3.75, which exceeds 3, so the curve is more peaked than the normal: leptokurtic. Dividing by μ₂ instead of μ₂² gives the wrong 15.