Parasitology and Immunology: Parasites, Their Life Cycles and the Immune Response

This chapter answers Section XL4.8 of XL4 Zoology, one of the five optional sections of the Life Sciences (XL) paper: “Nature of parasite, host-parasite relation, protozoan and helminthic parasites, the immune system, cellular and humoral immune response.” It defines parasitism and the kinds of host, explains how parasites are adapted to their hosts and how hosts respond, and sets out the standard protozoan and helminth parasites with their hosts, vectors, infective stages and life cycles. It then teaches the immune system: innate defences and lymphoid organs, antibodies and clonal selection, and T cells, MHC and cell-mediated killing, ending with how immunity deals with protozoa and worms. The numericals are antibody valency, serial-dilution titres, clonal expansion and merozoite multiplication.

1. The nature of parasitism and the kinds of host

Parasitism is a close association in which one partner, the parasite, lives on or in the other, the host, depends on it metabolically and usually harms it without killing it quickly. It differs from mutualism (both gain), commensalism (one gains, the other is unaffected) and from predation and parasitoidism, which kill. Ectoparasites (lice, ticks, fleas) live on the surface, endoparasites inside. An obligate parasite cannot complete its life without a host; a facultative one is normally free-living, like the amoeba Naegleria fowleri. A monoxenous parasite needs one host (Entamoeba, Ascaris), a heteroxenous one two or more (Plasmodium, Taenia).

Kinds of host
TermMeaningExample
Definitive hostHarbours the adult or sexual stageHuman for Taenia solium; female Anopheles for Plasmodium
Intermediate hostHarbours larval or asexual stagesPig for T. solium; human for Plasmodium; snail for flukes
Reservoir hostAnimal that maintains the infection and is a source for humansWild game and cattle for Trypanosoma brucei rhodesiense
Paratenic (transport) hostCarries the parasite without any developmentBridges a gap in the food chain between essential hosts
VectorTransmits the parasite between hostsBiological, with development inside (mosquito, tsetse, sandfly); mechanical, carried passively (house flies carrying cysts)
⚠️ Who is definitive for Plasmodium?
Fusion of gametes and sporogony happen in the mosquito, so the female Anopheles is the definitive host as well as the vector. The human, in which only asexual multiplication occurs, is the intermediate host, however ill it becomes.

2. Host–parasite relations: adaptation, evasion and coevolution

Parasites show morphological adaptations: attachment organs (suckers, the hooked scolex of tapeworms, the toothed buccal capsule of hookworms), loss of organs (tapeworms have no gut and absorb food across a tegument enlarged by microtriches) and resistant coverings (cuticle, tegument, cyst walls that survive drying and stomach acid). Physiological ones include anaerobic metabolism in the oxygen-poor gut and inhibitors of host enzymes. Reproductive ones offset the low odds of reaching a new host: enormous egg output, hermaphroditism in most flatworms, and asexual multiplication inside intermediate hosts (sporocysts and rediae of flukes, schizogony of Plasmodium).

Parasites also evade immunity. African trypanosomes switch their variant surface glycoprotein (VSG), so each wave of parasitaemia is antigenically new; P. falciparum varies its red-cell surface protein PfEMP1. Others hide inside cells: Plasmodium in red cells, which carry no MHC, Leishmania inside macrophages, Toxoplasma in a vacuole that does not fuse with lysosomes. Schistosomes coat their tegument with host molecules. Hosts evolve in return: the sickle-cell trait (HbAS) protects against severe falciparum malaria, a balanced polymorphism, and red cells lacking the Duffy antigen resist P. vivax. Some parasites alter host behaviour to aid transmission: rodents infected with Toxoplasma lose their aversion to cat odour. That a well-adapted parasite spares its host is a tendency, not a law; virulence is favoured when transmission depends on the damage itself.

3. Protozoan parasites

Standard protozoan parasites
ParasiteDisease; hosts or vectorInfective stage and routeKey feature
Entamoeba histolyticaAmoebic dysentery, liver abscess; humans onlyMature four-nucleate cyst, faecal–oralTrophozoites invade the colon wall (flask-shaped ulcers)
Giardia lambliaGiardiasis: malabsorption, fatty diarrhoeaFour-nucleate cyst, faecal–oral, often in waterBinucleate trophozoite clings by a ventral adhesive disc; does not invade
Trypanosoma bruceiAfrican sleeping sickness; tsetse fly (Glossina)Trypomastigote injected in the fly's salivaExtracellular in blood, later the CNS; VSG switching
Trypanosoma cruziChagas disease; triatomine (reduviid) bugTrypomastigotes in bug faeces rubbed into the bite or mucosaAmastigotes multiply inside cells, notably heart muscle
Leishmania donovaniVisceral leishmaniasis (kala-azar); sandfly (Phlebotomus)Promastigote injected by the sandflyAmastigotes multiply inside macrophages of spleen, liver and marrow
Toxoplasma gondiiToxoplasmosis; cat definitive, many mammals intermediateOocysts from cat faeces, tissue cysts in undercooked meat, across the placentaCongenital infection

The malaria parasite Plasmodium alternates between hosts. A female Anopheles injects sporozoites, which enter liver cells and multiply by exo-erythrocytic schizogony; the released merozoites invade red cells, pass through ring, trophozoite and schizont stages and burst out as new merozoites (erythrocytic schizogony). The synchronous bursting causes the fever paroxysm, every 48 h in P. vivax, P. ovale and P. falciparum (tertian) and every 72 h in P. malariae (quartan). Some merozoites become male and female gametocytes. In the mosquito gut these form gametes that fuse to a zygote; it becomes a motile ookinete, then an oocyst on the gut wall, where sporogony produces sporozoites that migrate to the salivary glands. Dormant liver hypnozoites of P. vivax and P. ovale cause relapses, and red cells infected with P. falciparum stick to vessel walls, which underlies cerebral malaria. Ronald Ross worked out transmission by mosquitoes while serving in India and received the 1902 Nobel Prize for it.

⚠️ Which stage, which host
Schizogony, the asexual multiplication, occurs in the human; fertilisation and sporogony occur in the mosquito. The stage infective to humans is the sporozoite; the stage infective to mosquitoes is the gametocyte.

4. Helminth parasites

Parasitic helminths belong to two phyla. Trematodes (flukes) are flat and unsegmented, with oral and ventral suckers, mostly hermaphrodite, and use a snail as first intermediate host, in which larvae multiply asexually. Cestodes (tapeworms) are ribbon-like: a scolex for attachment, a neck that buds off proglottids, and a strobila of hermaphrodite proglottids, with no gut. Nematodes (roundworms) are cylindrical and unsegmented, with a complete gut, a pseudocoelom, separate sexes (the male smaller, often with a curved tail) and a cuticle moulted four times.

Standard helminth parasites
ParasiteDefinitive hostIntermediate hostHow humans are infected; key point
Fasciola hepatica (liver fluke)Sheep and cattle; humans occasionallySnail (Lymnaea)Metacercariae encysted on water plants; egg → miracidium → sporocyst → redia → cercaria → metacercaria
Schistosoma (blood fluke)HumanSnailCercariae penetrate the skin in water; sexes separate
Taenia solium (pork tapeworm)HumanPigCysticerci in undercooked pork; scolex armed with hooks and four suckers
Taenia saginata (beef tapeworm)HumanCattleCysticerci in undercooked beef; scolex without hooks
Echinococcus granulosusDogSheep, cattle; humans accidentallyEggs from dog faeces; hydatid cysts in liver and lungs
Ascaris lumbricoidesHumanNoneEmbryonated eggs swallowed; larvae migrate through liver, heart and lungs, are coughed up and swallowed
Ancylostoma duodenale (hookworm)HumanNoneFilariform larvae penetrate the skin; blood-feeding causes iron-deficiency anaemia
Wuchereria bancrofti (filarial worm)HumanMosquito (Culex; also Anopheles, Aedes)Infective larvae deposited at the bite; microfilariae circulate at night; lymphatic filariasis
Enterobius vermicularis (pinworm)HumanNoneEggs, often by self-reinfection; females lay eggs on perianal skin at night
⚠️ Taenia solium makes the human either host
Eating cysticerci in pork gives an intestinal tapeworm, with the human as definitive host. Swallowing eggs gives cysticercosis, cysticerci in muscle and brain, with the human as intermediate host; neurocysticercosis is a common cause of seizures in India. Eggs of T. saginata do not cause human cysticercosis.

5. The immune system: innate defence and lymphoid organs

Innate immunity is present from birth, acts within minutes to hours, uses germline-encoded receptors and has no memory. It includes barriers (skin, mucus, lysozyme, stomach acid), phagocytes (neutrophils first, then macrophages), natural killer (NK) cells, complement, inflammation and antiviral type I interferons. Its pattern-recognition receptors, such as the Toll-like receptors, detect molecules common to microbes: TLR4 recognises bacterial lipopolysaccharide, TLR3 double-stranded RNA, TLR5 flagellin. Adaptive immunity, carried by lymphocytes, is specific and clonal, slower on first exposure, and leaves memory.

Primary lymphoid organs produce and select lymphocytes: the bone marrow (all blood cells; B-cell maturation) and the thymus (T-cell maturation). In birds B cells mature in the bursa of Fabricius, which gave B cells their letter. Secondary lymphoid organs, the lymph nodes, the spleen (for blood-borne antigen) and mucosa-associated tissue such as tonsils and Peyer's patches, are where naive lymphocytes meet antigen brought by dendritic cells.

Complement is activated by three routes: classical (C1q binding antibody on an antigen), lectin (mannose-binding lectin on microbial sugars) and alternative (spontaneous C3 hydrolysis on unprotected surfaces). All converge on a C3 convertase, giving opsonisation by C3b, inflammation and chemotaxis by C3a and C5a, and lysis by the membrane attack complex, C5b–C9. Innate defence is universal in animals (the Toll pathway was first found in Drosophila), but immunoglobulins, T-cell receptors and MHC, built by RAG-mediated V(D)J recombination, occur only in jawed vertebrates; lampreys and hagfish have a separately evolved lymphocyte receptor system.

6. Humoral immunity: antibodies and clonal selection

An antibody has two identical heavy chains and two identical light chains (κ or λ) joined by disulphide bonds. The variable domains of one heavy and one light chain form an antigen-binding site, shaped by three hypervariable loops (CDRs) on each chain; the heavy-chain constant region fixes the class and the effector function. Papain cuts at the hinge into two Fab fragments, each with one binding site, and one Fc; pepsin leaves one bivalent F(ab')2.

Antibody classes
ClassFormBinding sitesDistinctive role
IgGMonomer2Most abundant in serum; crosses the placenta; opsonises; dominant in secondary responses
IgMPentamer with J chain in serum10First antibody of a primary response; strongest complement activator; the monomer is a B-cell receptor
IgADimer with J chain and secretory component in secretions4Mucosal surfaces, milk and colostrum
IgEMonomer2Binds mast cells and basophils; allergy; defence against worms
IgDMonomer2B-cell receptor, with IgM, on naive B cells

Clonal selection (Burnet): each lymphocyte carries receptors of a single specificity, generated before any antigen is met by V(D)J recombination (RAG1 and RAG2) and junctional diversity. Antigen selects the matching clones, which divide (clonal expansion) and differentiate into antibody-secreting plasma cells and long-lived memory cells; self-reactive clones are deleted or silenced. For a protein antigen the B cell presents peptide on MHC class II to a helper T cell, which supplies CD40 ligand and cytokines; in the germinal centre the enzyme AID drives somatic hypermutation, which with selection gives affinity maturation, and class switching. A secondary response is faster, larger, mostly IgG and of higher affinity. Expansion is exponential, N = N0 × 2t/td: one cell dividing every 8 h for 4 days (12 divisions) gives 4,096 cells.

A titre is the reciprocal of the highest dilution of serum that still gives a detectable reaction. In a twofold series starting at 1:10, tube n holds a 1:(10 × 2n−1) dilution, so agglutination up to tube 6 means a titre of 320. A fourfold or greater rise between acute and convalescent sera points to a current infection. Active immunity is made by the host (infection, vaccine); passive immunity is borrowed antibody (maternal IgG across the placenta, antiserum).

7. Cell-mediated immunity and immunity to parasites

T cells see peptide bound to MHC. Class I molecules (an α chain with β2-microglobulin) sit on nearly all nucleated cells and present peptides of 8 to 10 amino acids from cytosolic proteins, cut by the proteasome and pumped into the ER by TAP, to CD8 T cells. Class II molecules (α and β chains) sit on dendritic cells, macrophages and B cells and present peptides from engulfed proteins to CD4 T cells. Activation needs signal 1 (T-cell receptor with peptide–MHC) and signal 2 (CD28 on the T cell binding B7 on the antigen-presenting cell); signal 1 alone causes anergy. In the thymus, positive selection keeps cells that recognise self MHC and negative selection removes strongly self-reactive ones.

  • Th1 (IFN-γ): activates macrophages; intracellular microbes and protozoa
  • Th2 (IL-4, IL-5, IL-13): switching to IgE, eosinophils, mast cells; worms
  • Th17 (IL-17): recruits neutrophils; extracellular bacteria and fungi
  • Treg (FoxP3; IL-10, TGF-β): suppresses responses and maintains tolerance; Tfh: helps B cells in germinal centres

Cytotoxic T cells kill infected cells with perforin and granzymes, which trigger apoptosis, and through Fas ligand. NK cells kill cells that have lost MHC class I (“missing self”) and antibody-coated cells by antibody-dependent cell-mediated cytotoxicity (ADCC) through their Fc receptor CD16. Against parasites the response depends on size and site. Worms are too big to engulf, so a Th2 response arms mast cells with IgE, recruits eosinophils that attack antibody-coated larvae, and increases mucus and gut contraction to expel the worms; eosinophilia and high IgE mark helminth infection. Intracellular protozoa such as Leishmania and Toxoplasma need Th1 help: IFN-γ activates macrophages to kill them. Mice infected with Leishmania major show this sharply: C57BL/6 mice mount a Th1 response and heal, BALB/c mice a Th2 response and develop progressive disease. In malaria, antibodies block sporozoites and merozoites, and CD8 T cells kill infected liver cells but not infected red cells, which lack MHC class I.

Key takeaways

  • A parasite lives on or in a host and depends on it metabolically. The definitive host carries the adult or sexual stage, the intermediate host larval or asexual stages; for Plasmodium the mosquito is definitive and the human intermediate.
  • Parasites adapt by attachment organs, loss of organs, resistant coverings, anaerobic metabolism and huge reproductive output, and evade immunity by antigenic variation, hiding in cells and host disguise; hosts answer with traits such as HbAS and Duffy negativity.
  • Know each standard parasite by host, vector and infective stage: Entamoeba cyst, Giardia cyst, tsetse for T. brucei, triatomine bug for T. cruzi, sandfly for Leishmania, sporozoite for humans and gametocyte for mosquitoes in malaria.
  • Flukes use snails and multiply as larvae; tapeworms need two hosts (T. solium eggs make humans intermediate hosts, causing cysticercosis); Ascaris, hookworm and pinworm need none, while Wuchereria needs a mosquito.
  • Innate immunity uses germline receptors such as TLRs, phagocytes, NK cells and three complement pathways converging on C3. Antibodies have two heavy and two light chains; IgM is a pentamer with 10 sites, secretory IgA a dimer with 4, IgG crosses the placenta. Titre = reciprocal of the highest positive dilution.
  • Clonal selection expands antigen-specific clones exponentially (N = N0 × 2n). MHC I presents cytosolic peptides to CD8 cells and MHC II engulfed ones to CD4 cells; Th1 and IFN-γ control intracellular protozoa, Th2, IgE and eosinophils control worms, and NK cells kill cells lacking MHC I.

Practice questions (18)

Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.

  1. Which statement correctly identifies the definitive host of Plasmodium vivax together with the reason?

    1. The human, because the parasite multiplies to by far its largest numbers inside human red blood cells
    2. The female Anopheles mosquito, because the fusion of gametes and sporogony take place in it
    3. The human, because the human liver is the only site in which dormant hypnozoites can persist
    4. The male Anopheles mosquito, because it carries sporozoites from person to person in its saliva
    Show answer

    Answer: B — The female *Anopheles* mosquito, because the fusion of gametes and sporogony take place in it

    The definitive host is the one in which sexual reproduction occurs. Gametocytes taken up by a female Anopheles form gametes that fuse in the mosquito gut, and sporogony follows on the gut wall, so the mosquito is definitive; the human, where only schizogony occurs, is intermediate. Large numbers of parasites in human blood are the tempting reason, but numbers do not define the host type. Male mosquitoes do not feed on blood and cannot transmit malaria.
  2. Which of the following are genuine adaptations of an adult tapeworm to life in the host's intestine?

    1. It has no digestive tract and absorbs nutrients across its tegument
    2. It depends on aerobic respiration, since the lumen of the host's gut is rich in oxygen
    3. It is protected by a chitinous exoskeleton that it moults as it grows
    4. Its proglottids are hermaphrodite and release very large numbers of eggs
    Show answer

    Answer: A — It has no digestive tract and absorbs nutrients across its tegument; D — Its proglottids are hermaphrodite and release very large numbers of eggs

    A tapeworm has lost its gut and absorbs food through a tegument covered with microtriches, and its hermaphrodite proglottids produce huge numbers of eggs to offset the low chance of reaching a new host. The gut lumen is poor in oxygen and adult tapeworms rely largely on anaerobic metabolism. Tapeworms have a living tegument, not a chitinous exoskeleton, and do not moult.
  3. Blood samples taken every few days from a person infected with Trypanosoma brucei show successive waves of parasitaemia, and the parasites of each wave are not recognised by antibodies raised against the previous wave. What best explains this?

    1. The parasites hide inside red blood cells, which display no MHC molecules to the patient's T cells
    2. The parasites coat their surface with host molecules, so that the antibodies no longer recognise them
    3. Synchronous schizogony in the liver releases each new wave of parasites at fixed intervals of 48 hours
    4. Some parasites switch to a different variant surface glycoprotein, escaping the existing antibody
    Show answer

    Answer: D — Some parasites switch to a different variant surface glycoprotein, escaping the existing antibody

    T. brucei is covered by one variant surface glycoprotein (VSG) at a time but carries a large repertoire of VSG genes. Antibody clears the dominant variant, while the few parasites that have switched to a new VSG grow out as the next wave. African trypanosomes live free in the blood, so hiding in red cells (a Plasmodium strategy) does not apply; coating with host molecules is the schistosome strategy and would not produce antigenically distinct waves; liver schizogony belongs to malaria.
  4. Which stage of Entamoeba histolytica is infective to humans, and why?

    1. The trophozoite passed in dysenteric stool, because it is the stage that invades the colon wall
    2. The binucleate trophozoite with a ventral disc, because it attaches firmly to the small intestine
    3. The mature four-nucleate cyst, because its wall survives outside the host and in stomach acid
    4. The oocyst shed in cat faeces, because it sporulates in the soil before it is swallowed
    Show answer

    Answer: C — The mature four-nucleate cyst, because its wall survives outside the host and in stomach acid

    The mature four-nucleate cyst survives in water and food and passes through the stomach, then excysts in the intestine; it is the infective stage. Trophozoites are the invasive stage but die quickly outside the body and in gastric acid, which makes them the tempting but wrong choice. A binucleate trophozoite with a ventral disc describes Giardia, and oocysts from cat faeces belong to Toxoplasma.
  5. Which of the following statements about the life cycle of Plasmodium are correct?

    1. Synchronous rupture of schizonts in red cells coincides with the fever paroxysm
    2. Gametocytes are the stage that infects humans when a mosquito bites
    3. Hypnozoites of P. vivax in the liver can cause relapses months after the first attack
    4. Sporogony takes place in human liver cells before red cells are invaded
    Show answer

    Answer: A — Synchronous rupture of schizonts in red cells coincides with the fever paroxysm; C — Hypnozoites of *P. vivax* in the liver can cause relapses months after the first attack

    The paroxysm follows the synchronous release of merozoites, toxins and debris when schizonts burst, and P. vivax (like P. ovale) leaves dormant hypnozoites in the liver that reactivate as relapses. Humans are infected by sporozoites; gametocytes infect the mosquito. The multiplication in liver cells is exo-erythrocytic schizogony; sporogony occurs only in the mosquito.
  6. In a simple model of an untreated malaria infection, each infected red cell releases 16 merozoites at the end of a 48-hour erythrocytic cycle, every merozoite invades a fresh red cell, and no parasites are cleared. Starting from 1,000 freshly infected red cells at time zero, how many red cells are infected after 6 days?

    Numerical answer — type the value.

    Show answer

    Answer: 4096000

    6 days = 144 h = 144 ÷ 48 = 3 complete cycles. Each cycle multiplies the infected cells by 16, so the number is 1,000 × 16³ = 1,000 × 4,096 = 4,096,000. Counting six cycles (one per day) is the usual slip.
  7. A person accidentally swallows eggs of Taenia solium passed by a tapeworm carrier. What is the most likely consequence?

    1. An adult tapeworm develops in the small intestine, since the human is the definitive host
    2. Cysticerci develop in tissues such as muscle and brain, the human acting as an intermediate host
    3. Nothing happens, because the eggs can hatch only after a period of development inside a snail host
    4. Hydatid cysts form in the liver, because the larvae grow into large fluid-filled brood capsules
    Show answer

    Answer: B — Cysticerci develop in tissues such as muscle and brain, the human acting as an intermediate host

    Eggs of T. solium hatch in the human intestine, and the larvae cross the gut wall and lodge in muscle, eye and brain as cysticerci: cysticercosis, with the human in the role normally taken by the pig. An intestinal tapeworm arises only from eating cysticerci in undercooked pork, which is the tempting confusion. Snails are intermediate hosts of flukes, not tapeworms, and hydatid cysts are larvae of Echinococcus.
  8. Which helminth typically infects humans when a larva living in moist soil penetrates the skin of bare feet?

    1. Ascaris lumbricoides
    2. Enterobius vermicularis
    3. Taenia saginata
    4. Ancylostoma duodenale
    Show answer

    Answer: D — *Ancylostoma duodenale*

    The filariform larva of the hookworm Ancylostoma duodenale develops in moist soil and penetrates the skin. Ascaris and Enterobius infect by swallowed eggs; Ascaris is tempting because its larvae also migrate through the lungs, but they hatch from swallowed eggs. Taenia saginata is acquired by eating cysticerci in beef.
  9. Deworming dogs regularly reduces human hydatid disease in a sheep-rearing district, whereas surgically treating infected people has no effect on transmission. Why?

    1. Humans are accidental intermediate hosts whose cysts dogs do not eat, so the cycle runs between dogs and livestock
    2. Humans are the definitive host, but the eggs they pass are destroyed in sewage before ever reaching grazing sheep
    3. Dogs are the intermediate host, and the hydatid cysts in their livers release the eggs that infect people
    4. Sheep are the definitive host, and dogs merely carry the eggs mechanically on their fur to people
    Show answer

    Answer: A — Humans are accidental intermediate hosts whose cysts dogs do not eat, so the cycle runs between dogs and livestock

    Echinococcus granulosus lives as an adult in the dog's intestine and as hydatid cysts in sheep and cattle; dogs are infected by eating offal containing cysts. A human with a cyst is a dead end, because no dog eats it, so treating people removes no source of eggs, while deworming dogs cuts egg output at its only source. The adult worm does not live in humans, dogs are not intermediate hosts, and sheep do not harbour the adult.
  10. What is the bursa of Fabricius?

    1. A secondary lymphoid organ of mammals that filters antigens from the blood
    2. The primary lymphoid organ of birds in which B lymphocytes mature
    3. The organ of reptiles in which developing T cells undergo positive selection
    4. Mucosa-associated lymphoid tissue lining the gut of bony fishes
    Show answer

    Answer: B — The primary lymphoid organ of birds in which B lymphocytes mature

    The bursa of Fabricius is a cloacal outgrowth in birds where B cells mature, and the B of B cell comes from it. The secondary lymphoid organ that filters blood in mammals is the spleen, positive selection of T cells takes place in the thymus, and fish have no bursa.
  11. Which of the following statements about innate immunity are correct?

    1. The alternative pathway of complement can be activated without any antibody
    2. NK cells recognise their targets with receptors assembled by RAG-mediated V(D)J recombination
    3. C3b deposited on a microbe acts as an opsonin that promotes phagocytosis
    4. Toll-like receptor 4 recognises the lipopolysaccharide of Gram-negative bacteria
    Show answer

    Answer: A — The alternative pathway of complement can be activated without any antibody; C — C3b deposited on a microbe acts as an opsonin that promotes phagocytosis; D — Toll-like receptor 4 recognises the lipopolysaccharide of Gram-negative bacteria

    The alternative pathway starts from spontaneous C3 hydrolysis on unprotected surfaces, C3b is the main complement opsonin, and TLR4 is the lipopolysaccharide receptor. NK cells are innate lymphocytes whose activating and inhibitory receptors are germline-encoded; V(D)J recombination builds only B- and T-cell receptors.
  12. Count theoretical antigen-binding sites. A sample contains 3 molecules of pentameric serum IgM, 2 molecules of dimeric secretory IgA and 5 molecules of monomeric IgG. What is the total number of antigen-binding sites?

    Numerical answer — type the value.

    Show answer

    Answer: 48

    Each antibody monomer has two binding sites. Pentameric IgM: 5 × 2 = 10 sites, so 3 × 10 = 30. Dimeric secretory IgA: 2 × 2 = 4 sites, so 2 × 4 = 8. IgG: 2 sites, so 5 × 2 = 10. Total = 30 + 8 + 10 = 48. (Large antigens may engage only about half the IgM sites, but the stem asks for theoretical valency.)
  13. Paired sera from a patient are tested by tube agglutination in a twofold serial dilution series that starts at 1:20 in tube 1. The acute-phase serum agglutinates up to tube 3 and the convalescent serum up to tube 6, with no agglutination in later tubes. Taking the titre as the reciprocal of the highest dilution that agglutinates, by what factor has the titre risen?

    Numerical answer — type the value.

    Show answer

    Answer: 8

    Tube n holds 1:(20 × 2n−1). Tube 3 is 1:80 and tube 6 is 1:640, so the titres are 80 and 640, and the rise is 640 ÷ 80 = 8-fold (three doubling steps, 2³). A rise of fourfold or more supports a current infection.
  14. Samples of a rabbit IgG antibody against sheep red cells are digested separately with papain and with pepsin, and the fragments are purified. Which fragment can still agglutinate sheep red cells?

    1. The Fab fragments from papain, because each one still carries an antigen-binding site
    2. The Fc fragment from papain, because it retains the hinge region that links the arms
    3. The F(ab')2 fragment from pepsin, because it keeps two linked antigen-binding sites
    4. No fragment can, because agglutination needs the Fc region to activate complement
    Show answer

    Answer: C — The F(ab')2 fragment from pepsin, because it keeps two linked antigen-binding sites

    Agglutination requires cross-linking, so a fragment must carry at least two antigen-binding sites. Pepsin cuts below the hinge disulphides and leaves a bivalent F(ab')2 that can bridge two cells. Papain cuts above them, giving univalent Fab fragments that bind but cannot cross-link, which is why the Fab option is the tempting wrong answer; Fc has no antigen-binding site, and agglutination does not need complement.
  15. After a viral infection, 50 naive CD8 T cells specific for one viral peptide are activated. Each divides every 8 hours for 4 days with no cell death. In the contraction phase that follows, 95% of the expanded cells die and the rest persist as memory cells. How many memory cells remain?

    Numerical answer — type the value.

    Show answer

    Answer: 10240

    4 days = 96 h = 96 ÷ 8 = 12 divisions, so each cell gives 2¹² = 4,096 cells and the clone reaches 50 × 4,096 = 204,800 cells. 5% survive contraction: 0.05 × 204,800 = 10,240 memory cells.
  16. A virus-infected cell line lacks a functional TAP transporter. Compared with infected cells that have TAP, how will these cells fare against cytotoxic lymphocytes?

    1. They show little peptide-loaded MHC class I, so CD8 T cells recognise them poorly but NK cells kill them readily
    2. They cannot load peptides onto MHC class II, so CD4 T cells ignore them while CD8 T cells kill them as usual
    3. They overload their surface with empty MHC class I, so CD8 T cells kill them faster and NK cells spare them
    4. They are unaffected, because TAP works only in B cells, where it moves newly made antibody into the ER
    Show answer

    Answer: A — They show little peptide-loaded MHC class I, so CD8 T cells recognise them poorly but NK cells kill them readily

    TAP pumps cytosolic peptides into the ER, where they stabilise newly made MHC class I. Without it few peptide–class I complexes reach the surface, so CD8 T cells, which need them, recognise the cells poorly, while NK cells, which kill cells lacking class I (missing self), kill them more readily. TAP serves the class I pathway, not class II, which ends the tempting class II option; empty class I is unstable rather than abundant; and TAP is a peptide transporter present in nearly all nucleated cells.
  17. Chronic infection with intestinal helminths typically raises which pair of laboratory values, and through which response?

    1. Blood neutrophil count and IFN-γ, through a Th1 response
    2. NK-cell count and type I interferon, through innate antiviral pathways
    3. Serum IgE and blood eosinophil count, through a Th2 response
    4. Serum IgM and complement C3, through the lectin pathway
    Show answer

    Answer: C — Serum IgE and blood eosinophil count, through a Th2 response

    Worms drive a Th2 response: IL-4 and IL-13 switch B cells to IgE, and IL-5 expands and activates eosinophils, so high IgE and eosinophilia are the classic laboratory signs. A Th1 response with IFN-γ is the tempting alternative but is directed at intracellular microbes, and type I interferons and NK cells are antiviral; the lectin pathway is not a hallmark of worm infection.
  18. BALB/c mice infected with Leishmania major develop progressive lesions with a Th2-dominated response, whereas C57BL/6 mice heal. If BALB/c mice are given a neutralising antibody against IL-4 at the time of infection, what is the most likely outcome?

    1. Lesions worsen, because IL-4 is the cytokine that activates macrophages to kill amastigotes
    2. No change, because protection against Leishmania depends on antibody, not on T-cell cytokines
    3. Lesions worsen, because blocking IL-4 removes the IgE needed to destroy infected macrophages
    4. The response shifts to Th1 and IFN-γ-activated macrophages, so the mice control the infection
    Show answer

    Answer: D — The response shifts to Th1 and IFN-γ-activated macrophages, so the mice control the infection

    Leishmania amastigotes live inside macrophages and are killed only when IFN-γ from Th1 cells activates those macrophages. IL-4 drives and maintains the Th2 bias of BALB/c mice; neutralising it early lets a Th1 response develop, and the mice behave like resistant strains. IFN-γ, not IL-4, activates macrophages, and antibody and IgE cannot reach parasites hidden inside macrophages.