Petroleum Production Operations: Completion, Workover, Formation Damage and Stimulation, Artificial Lift, Nodal Analysis, Surface Processing, Flow Assurance and Equipment

Section 5 of the GATE Petroleum Engineering (PE) paper, in one chapter and the syllabus’s order: well equipment and completion techniques; well production problems and their mitigation; well servicing and workover operations, and workover and completion fluids; formation damage and well stimulation; artificial lift; field processing of oil and gas, storage and transportation, and metering; production system analysis and optimisation — inflow performance, tubing performance and nodal analysis — and production testing; multiphase flow in tubing and flowlines; flow assurance problems and their remedies; and the surface equipment the section closes on: pressure vessels, storage tanks, shell-and-tube heat exchangers, pumps and compressors. The constants used are stated where they appear; rates are in STB/d and pressures in psi unless the stem says otherwise.

1. Well equipment and completion techniques

A producing well is capped by the wellhead (casing heads and spools that hang and seal each casing string, and the tubing head that hangs the tubing) and the Christmas tree of master valves, wing valve, swab valve and choke that controls flow at surface. Downhole, the production tubing carries the fluid; a packer seals the tubing-casing annulus so that the casing is protected from well pressure and corrosive fluid; a subsurface safety valve (SSSV), usually tubing-retrievable and held open by control-line pressure, closes automatically if surface control is lost; landing nipples accept wireline plugs and gauges, sliding sleeves open or close communication between tubing and annulus, and side-pocket mandrels hold gas-lift valves.

Completion techniques differ in how the reservoir meets the well. An open-hole completion leaves the pay uncased — maximum inflow, no zonal control, only for competent rock. A cased-and-perforated completion cements casing across the pay and opens it with shaped-charge perforating guns, giving selective zonal control; perforating underbalanced (wellbore pressure below reservoir pressure) cleans the perforation tunnels of crushed-zone debris at once. A liner completion hangs a short string across the pay. Sand control completions — gravel packs, frac packs, standalone screens — hold back formation sand in weak rock. Completions are single or multiple (dual completions produce two zones separately through two tubing strings), and intelligent completions add remotely operated downhole valves and gauges.

2. Production problems, servicing and workover, workover fluids, formation damage and stimulation

The common well production problems are sand production (erosion, fill, collapse), excessive water or gas (coning, channelling behind casing, early breakthrough), paraffin and asphaltene deposition, scale, corrosion, emulsions and liquid loading of gas wells. Well servicing is the routine work done without pulling the completion — wireline and slickline runs, coiled tubing (a continuous reel of tubing run under pressure for cleanouts, nitrogen lifts, acid placement and logging) and snubbing (jointed pipe forced into a live well). A workover is heavier: it kills the well and pulls or modifies the completion to repair casing, isolate water, recomplete to a new zone, change the lift method or sidetrack.

Workover and completion fluids must control pressure while doing the least possible harm to the pay, so they are solids-free clear brines whose density is chosen by salt: sodium and potassium chloride for light fluids, calcium chloride and calcium bromide for heavier ones, and zinc bromide blends for the heaviest. They are filtered to remove fine solids, and chosen to be compatible with the formation water (to avoid scale) and the clays (to avoid swelling). Formation damage is any reduction of near-wellbore permeability: fines migration, clay swelling, solids and filtrate invasion from mud and cement, emulsion and water blocks, wettability alteration, scale and organic deposits, and perforation crushed zones. It is quantified by the skin factor s, the extra dimensionless pressure drop at the well: a damaged well has s > 0, a stimulated one s < 0.

Stimulation removes or bypasses damage. Matrix acidizing injects acid below fracture pressure: in carbonates hydrochloric acid (typically 15% HCl) dissolves the rock and cuts conductive wormholes through the damaged zone; in sandstones the damage (clays, fines) is dissolved by mud acid, an HCl-HF blend, preceded by an HCl preflush that removes carbonates so that insoluble calcium fluoride does not precipitate, and followed by an overflush. Hydraulic fracturing pumps fluid above the fracture pressure to split the rock, then carries proppant (sand or ceramic) into the fracture to hold it open, creating a conductive path of half-length x_f. Its effectiveness is measured by the dimensionless fracture conductivity F_CD = k_f w/(k x_f); acid fracturing in carbonates etches the fracture faces unevenly instead of propping them.

⚠️ Mud acid is for sandstones, and never without a preflush
HF reacts with calcium carbonate to form calcium fluoride, which precipitates and plugs the rock it was meant to clean. So HF goes only into sandstones, after an HCl preflush has removed the carbonate cement and flushed calcium-rich formation water away. In a limestone, plain HCl is both the cheaper and the correct acid.

3. Artificial lift, production system analysis and production testing

A well flows naturally while reservoir pressure can lift the fluid column to the separator; when it cannot, artificial lift adds energy. Sucker-rod (beam) pumping: a surface pumping unit reciprocates a rod string that works a downhole plunger pump; theoretical displacement is PD = 0.1166 S_p N D² bbl/d, with plunger stroke S_p in inches, N strokes per minute and plunger diameter D in inches. Gas lift injects gas through valves in side-pocket mandrels to lighten the fluid gradient in the tubing (continuous) or to push slugs to surface (intermittent). The electrical submersible pump (ESP) is a multistage centrifugal pump driven by a downhole motor, for high rates. The progressing-cavity pump (PCP) suits viscous and sandy oil. Hydraulic (piston or jet) pumps use a power fluid; plunger lift unloads liquid from gas wells.

Production system analysis follows the fluid from the reservoir to the separator and treats every component as a pressure loss. The inflow performance relationship (IPR) links rate to bottom-hole flowing pressure: above the bubble point it is the straight line q = J(p̄ − p_wf); for a solution-gas-drive well below the bubble point, Vogel’s relation q/q_max = 1 − 0.2(p_wf/p̄) − 0.8(p_wf/p̄)² describes the curve that gas liberation produces. The tubing performance relationship (TPR, or vertical lift performance) gives the p_wf needed to lift each rate to the wellhead against hydrostatic head, friction and acceleration. Nodal analysis picks a node — usually the bottom of the tubing — and plots the pressure available from upstream (the IPR) against the pressure required downstream (the TPR); their intersection is the operating point, and changes to tubing size, choke, separator pressure, lift or stimulation are evaluated by how they move it. Production testing routes a well through a test separator to measure its oil, gas and water rates, gas-oil ratio and water cut, which feed allocation and the IPR.

Artificial lift methods
MethodPrincipleSuited to
Sucker-rod pumpPositive-displacement plunger worked by rodsLow to moderate rates, onshore, moderate depth
Gas liftInjected gas lowers the flowing gradientDeviated and offshore wells, sand, gas available
ESPMultistage centrifugal pump with downhole motorHigh liquid rates, high water cut; sensitive to gas and sand
PCPHelical rotor turning in an elastomer statorViscous oil and sandy fluid, shallow wells
Jet pumpPower fluid through a nozzle and throatNo moving parts downhole; tolerant of solids
Plunger liftFree plunger driven by the well’s own gasLiquid loading in gas wells

4. Field processing, storage and transportation, and metering

Well streams are separated at the surface. Two-phase separators divide gas from liquid; three-phase separators also divide oil from free water. Separation happens by gravity settling, helped by inlet diverters, mist extractors and enough retention time for liquid to degas and for water droplets to fall out — retention time is simply liquid volume in the vessel divided by liquid flow rate. Stage separation at successively lower pressures recovers more stock-tank liquid than a single flash. Emulsions are broken by heat, chemicals (demulsifiers), electrostatic fields and time in heater-treaters and electrostatic treaters. Gas is dehydrated by glycol (triethylene glycol) absorption or solid desiccants to prevent hydrates and corrosion, sweetened by amine absorption to remove H₂S and CO₂, and conditioned for its dew point.

Crude is held in atmospheric storage tanks: fixed-roof tanks for low-volatility liquids, and floating-roof tanks, whose roof rides on the liquid surface and eliminates the vapour space, for volatile crude — cutting evaporation losses and the fire risk of a flammable vapour space. Oil and gas move by pipeline (the cheapest per barrel over land, with pumping or compressor stations), by tanker at sea and by road or rail for small volumes. Metering is the basis of sale and allocation: gas by orifice meters (differential pressure across a plate, flow ∝ √Δp), turbine, ultrasonic and Coriolis meters; oil by positive-displacement, turbine and Coriolis (direct mass-flow) meters, and at custody transfer by a LACT unit (lease automatic custody transfer) that meters, samples and checks the quality of oil entering a pipeline, calibrated against a meter prover.

5. Multiphase flow in tubing and flowlines, and flow assurance

When gas and liquid flow together the pressure gradient has three parts — elevation (hydrostatic, usually dominant in vertical wells), friction and acceleration — and depends on the flow pattern. In vertical upward flow, as the gas rate rises the patterns run bubble (dispersed small bubbles), slug (large Taylor bubbles separated by liquid slugs), churn (chaotic), annular (a gas core with a liquid film on the wall) and mist (droplets in gas). Because gas slips past liquid, the in-situ liquid fraction, the holdup H_L, exceeds the no-slip fraction, and it is the holdup that sets the mixture density of the hydrostatic term. Empirical and mechanistic correlations predict holdup and friction — Hagedorn-Brown for vertical wells and Beggs-Brill for inclined and horizontal lines are the classic names — and horizontal flowlines add stratified and wavy patterns and severe slugging at riser bases.

Flow assurance: problems and remedies
ProblemCauseRemedies
Wax (paraffin)Cooling below the wax appearance temperatureInsulation and heating, pigging, wax inhibitors and pour-point depressants, hot oiling
AsphaltenesPressure drop toward the bubble point, blending, CO₂ or acid contactDispersants and inhibitors, solvent (aromatic) washes, pressure management
Gas hydratesWater and light gas at high pressure and low temperatureThermodynamic inhibitors (methanol, MEG), kinetic inhibitors and anti-agglomerants, dehydration, insulation, depressurisation
ScaleMixing incompatible waters; pressure and temperature change (CaCO₃, BaSO₄)Scale-inhibitor squeezes, sulphate removal from injection water, acid or mechanical removal
CorrosionCO₂ (sweet), H₂S (sour), oxygen, bacteriaCorrosion inhibitors, resistant alloys, coatings, cathodic protection, oxygen scavenging
Slugging and emulsionsTerrain and riser geometry; shear of oil and waterSlug catchers, gas lift in risers, topside choking; demulsifiers and heat
🎯 Why methanol stops hydrates
A hydrate is a solid cage of water molecules around small gas molecules, stable only at high pressure and low temperature. Methanol and MEG lower the activity of the water, shifting the hydrate equilibrium curve to lower temperatures, so the line operates outside the hydrate region — a thermodynamic effect, needing large doses. Kinetic inhibitors and anti-agglomerants work at far lower doses by slowing hydrate growth or keeping crystals small and dispersed.

6. Pressure vessels, storage tanks, shell-and-tube heat exchangers, pumps and compressors

Separators, treaters and scrubbers are pressure vessels. For a thin-walled cylinder of diameter D and wall thickness t under internal pressure p, the hoop stress is σ_h = pD/(2t) and the longitudinal stress pD/(4t) — hoop is twice longitudinal, so the wall is sized for hoop stress and a cylindrical vessel splits lengthwise; a sphere carries pD/(4t) in every direction. Code design adds a corrosion allowance and a joint efficiency, and every vessel is protected by a pressure relief valve set at or below its maximum allowable working pressure. Shell-and-tube heat exchangers pass one fluid through a tube bundle and the other across it inside a shell, guided by baffles; the duty is Q = UA·ΔT_lm, with the log-mean temperature difference ΔT_lm = (ΔT₁ − ΔT₂)/ln(ΔT₁/ΔT₂), which is larger for counter-current than for co-current flow between the same terminal temperatures; fouling adds resistance and lowers U over time.

Pumps move liquid. Centrifugal pumps add head by impeller speed, deliver smooth flow that falls as head rises along the pump curve, and are chosen at their best-efficiency point; positive-displacement pumps (reciprocating, gear, screw) deliver nearly constant flow whatever the discharge pressure and must never be run against a closed valve without relief. Every pump needs the net positive suction head available (NPSH_A) to exceed the NPSH required by the pump, or the liquid flashes at the impeller eye and cavitation erodes it. Compressors move gas: reciprocating compressors for high ratios and modest flows, centrifugal compressors for large flows at moderate ratios, and screw compressors in between. Compression heats the gas, so a large overall ratio is split into stages with intercooling, and for minimum total work the stage ratios are equal: with n stages each has ratio r = (p_d/p_s)^(1/n). Centrifugal compressors must be kept away from surge, the unstable low-flow reversal at the left of the performance map.

Key takeaways

  • A completion is wellhead, tree, tubing, packer and SSSV; perforate underbalanced; workover fluids are solids-free brines; skin s > 0 means damage.
  • HCl for carbonates, HCl-HF mud acid after an HCl preflush for sandstones; fractures are rated by F_CD = k_f w/(k x_f).
  • J = q/(p̄ − p_wf); Vogel q/q_max = 1 − 0.2(p_wf/p̄) − 0.8(p_wf/p̄)²; the operating point is where IPR meets TPR; rod-pump displacement is 0.1166 S_p N D² bbl/d.
  • Vertical multiphase flow runs bubble, slug, churn, annular, mist; holdup exceeds no-slip fraction; hydrates are fought with methanol or MEG, wax with heat and pigging, scale with inhibitors.
  • Hoop stress pD/(2t); Q = UA·ΔT_lm; NPSH_A must exceed NPSH_R; equal compression ratios per stage, r = (p_d/p_s)^(1/n).

Practice questions (16)

Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.

  1. A well produces 800 STB/d at a flowing bottom-hole pressure of 1500 psi from a reservoir at an average pressure of 2500 psi. Its productivity index is ______ STB/d/psi.

    Numerical answer — type the value.

    Show answer

    Answer: 0.8

    J = q/(p̄ − p_wf) = 800/(2500 − 1500) = 800/1000 = 0.8 STB/d/psi. On a straight-line IPR the absolute open flow would be J × p̄ = 0.8 × 2500 = 2000 STB/d.
  2. A solution-gas-drive well in a reservoir at its bubble-point pressure of 2000 psi produces 600 STB/d at a flowing bottom-hole pressure of 1200 psi. By Vogel’s relation the maximum (absolute open flow) rate is ______ STB/d (to the nearest whole number).

    Numerical answer — type the value.

    Show answer

    Answer: 1014

    p_wf/p̄ = 1200/2000 = 0.6. q/q_max = 1 − 0.2(0.6) − 0.8(0.36) = 1 − 0.12 − 0.288 = 0.592, so q_max = 600/0.592 = 1013.5, which is 1014 STB/d. A straight-line IPR through the same point would give 600 × 2000/800 = 1500 STB/d, overstating the well.
  3. In nodal analysis with the node at the bottom of the tubing, the operating point of the well is

    1. the intersection of the inflow performance curve and the tubing performance curve
    2. the maximum of the inflow performance curve
    3. the rate at which the tubing performance curve has its minimum
    4. the absolute open flow of the well
    Show answer

    Answer: A — the intersection of the inflow performance curve and the tubing performance curve

    At the node, the pressure the reservoir can deliver (IPR) must equal the pressure the tubing needs to lift that rate to surface (TPR); only one rate satisfies both, and that is where the curves cross. The absolute open flow assumes zero bottom-hole pressure, which no tubing can achieve.
  4. A sucker-rod pump has a plunger diameter of 2 in, an effective plunger stroke of 100 in and runs at 10 strokes per minute. Using PD = 0.1166 S_p N D² bbl/d, its theoretical displacement is ______ bbl/d (to one decimal place).

    Numerical answer — type the value.

    Show answer

    Answer: 466.4

    PD = 0.1166 × 100 × 10 × 2² = 0.1166 × 4000 = 466.4 bbl/d. Check from first principles: plunger area π × 2²/4 = 3.1416 in²; × 100 in × 10 × 1440 min/d = 4.524 × 10⁶ in³/d; ÷ 9702 in³/bbl = 466.3 bbl/d.
  5. Continuous gas lift increases a well’s production mainly by

    1. reducing the density, and hence the hydrostatic gradient, of the fluid column in the tubing
    2. raising the reservoir pressure
    3. increasing the permeability near the wellbore
    4. cooling the produced fluid
    Show answer

    Answer: A — reducing the density, and hence the hydrostatic gradient, of the fluid column in the tubing

    Injected gas aerates the liquid in the tubing, so the flowing pressure needed at the bottom to lift it falls; a lower p_wf gives a higher rate from the same IPR. Gas lift does nothing to the reservoir pressure or the near-well permeability.
  6. For matrix acidizing of a damaged sandstone, the usual treatment is

    1. an HCl preflush, then HCl-HF mud acid, then an overflush
    2. HF alone, with no preflush
    3. acetic acid pumped above the fracture pressure
    4. plain 15% HCl to create wormholes
    Show answer

    Answer: A — an HCl preflush, then HCl-HF mud acid, then an overflush

    Sandstone damage is clays and fines, which HF dissolves; but HF with calcium precipitates CaF₂, so an HCl preflush removes carbonates and calcium-bearing water first, and an overflush pushes spent acid away from the well. Wormholing with plain HCl is the carbonate treatment, and pumping above fracture pressure is fracturing, not matrix acidizing.
  7. A propped fracture has proppant-pack permeability 100 000 md, propped width 0.01 ft and half-length 500 ft in a 1 md formation. Its dimensionless fracture conductivity F_CD = k_f w/(k x_f) is ______.

    Numerical answer — type the value.

    Show answer

    Answer: 2

    F_CD = (100 000 × 0.01)/(1 × 500) = 1000/500 = 2. The fracture conductivity k_f w is 1000 md·ft, and it is compared with the formation’s ability to feed it over the half-length, k x_f = 500 md·ft.
  8. Which of the following are properties wanted in a workover or completion fluid? (More than one option may be correct.)

    1. Enough density to control formation pressure
    2. Freedom from suspended solids
    3. Compatibility with formation water and clays
    4. A high content of bentonite to build a thick filter cake
    Show answer

    Answer: A — Enough density to control formation pressure; B — Freedom from suspended solids; C — Compatibility with formation water and clays

    A workover fluid is in direct contact with the open pay, so it must control pressure with a clear brine, carry no solids that could plug perforations or pore throats, and not cause scale or clay swelling. A bentonite cake is exactly the kind of solids plugging a clear completion fluid is meant to avoid.
  9. A three-phase separator holds 50 bbl of liquid and handles a liquid rate of 7200 bbl/d. The liquid retention time is ______ minutes.

    Numerical answer — type the value.

    Show answer

    Answer: 10

    7200 bbl/d is 7200/1440 = 5 bbl/min, and retention time = volume/rate = 50/5 = 10 minutes. Equivalently 50/7200 of a day is 0.006944 d × 1440 = 10 min.
  10. Volatile crude oil is preferably stored in floating-roof tanks because they

    1. eliminate the vapour space above the liquid, reducing evaporation losses and fire risk
    2. can hold the oil at a higher pressure
    3. heat the oil to keep wax in solution
    4. separate water from the oil
    Show answer

    Answer: A — eliminate the vapour space above the liquid, reducing evaporation losses and fire risk

    The roof rests on the liquid and rises and falls with it, so there is almost no space for vapour to collect and be breathed out as the tank fills and empties or warms and cools. Storage tanks are atmospheric; they are not pressure vessels, heaters or separators.
  11. In vertical upward gas-liquid flow in tubing, as the gas rate increases at a fixed liquid rate, the usual sequence of flow patterns is

    1. bubble, slug, churn, annular
    2. annular, churn, slug, bubble
    3. stratified, wavy, slug, annular
    4. slug, bubble, annular, churn
    Show answer

    Answer: A — bubble, slug, churn, annular

    Small dispersed bubbles coalesce into Taylor bubbles (slug flow), which break down into chaotic churn flow, and at high gas velocity the liquid is pushed to the wall as a film around a gas core (annular), finally mist. Stratified and wavy patterns belong to horizontal pipes, where gravity separates the phases.
  12. Which of the following help to prevent gas-hydrate formation in a subsea flowline? (More than one option may be correct.)

    1. Injecting methanol or monoethylene glycol
    2. Insulating or heating the line to stay above the hydrate temperature
    3. Dehydrating the gas before it enters the line
    4. Raising the operating pressure at constant temperature
    Show answer

    Answer: A — Injecting methanol or monoethylene glycol; B — Insulating or heating the line to stay above the hydrate temperature; C — Dehydrating the gas before it enters the line

    Hydrates need water, light gas, high pressure and low temperature. Methanol or MEG shift the equilibrium curve; insulation or heating keeps the line warm; dehydration removes the water. Raising the pressure at a given temperature moves the line further into the hydrate-stable region, so it promotes hydrates rather than preventing them.
  13. A thin-walled cylindrical separator of internal diameter 1.5 m and wall thickness 15 mm operates at an internal pressure of 2 MPa. The hoop stress in the wall is ______ MPa.

    Numerical answer — type the value.

    Show answer

    Answer: 100

    σ_hoop = pD/(2t) = 2 × 1500/(2 × 15) = 3000/30 = 100 MPa (millimetres cancel). The longitudinal stress is half of that, pD/(4t) = 50 MPa, which is why a cylinder is sized on hoop stress.
  14. In a counter-current shell-and-tube heat exchanger, crude is heated from 30 °C to 70 °C by a hot stream cooling from 150 °C to 90 °C. The log-mean temperature difference is ______ °C (to one decimal place).

    Numerical answer — type the value.

    Show answer

    Answer: 69.5

    Counter-current: ΔT₁ = 150 − 70 = 80 °C at the hot inlet end, ΔT₂ = 90 − 30 = 60 °C at the other. ΔT_lm = (80 − 60)/ln(80/60) = 20/0.2877 = 69.5 °C. It lies between the two end differences and just below their arithmetic mean of 70 °C, as a log mean must.
  15. Gas is to be compressed from 100 psia to 900 psia in two stages with perfect intercooling. For minimum total work, the compression ratio of each stage is ______.

    Numerical answer — type the value.

    Show answer

    Answer: 3

    The overall ratio is 900/100 = 9, and equal stage ratios minimise the work: r = 9^(1/2) = 3, so the interstage pressure is 300 psia. Check: 300/100 = 3 and 900/300 = 3.
  16. Cavitation in a centrifugal pump is avoided by ensuring that

    1. the net positive suction head available exceeds that required by the pump
    2. the discharge valve is kept closed at start-up
    3. the pump runs well to the left of its best-efficiency point
    4. the suction pressure is kept as low as possible
    Show answer

    Answer: A — the net positive suction head available exceeds that required by the pump

    Cavitation starts when the pressure at the impeller eye falls to the liquid’s vapour pressure; NPSH_A > NPSH_R keeps it above. Lowering suction pressure makes cavitation worse, and running far from the best-efficiency point causes recirculation and vibration rather than preventing cavitation.