Enhanced Oil Recovery: Mechanisms, Screening, Pattern Flooding and Sweep, Displacement Efficiency, and Chemical, Miscible, Thermal, Microbial and Low-Salinity Methods

Section 10 of the GATE Petroleum Engineering (PE) paper, in one chapter and the syllabus’s order: the basic principles and mechanism of enhanced oil recovery (EOR); the screening of EOR processes; the concept of pattern flooding, recovery efficiency and permeability heterogeneity; macroscopic and microscopic displacement efficiency; and the EOR methods the paper names — chemical flooding, miscible flooding, thermal recovery (steam stimulation, hot-water and steam flooding, in-situ combustion), microbial EOR and low-salinity water flooding. Two dimensionless groups organise the whole subject: the mobility ratio, which decides how well a displacing fluid sweeps the reservoir, and the capillary number, which decides how much oil it leaves behind in the pores it does sweep.

1. Why oil is left behind, and the mechanism of EOR

After primary recovery and waterflooding, typically well over half the original oil remains, for two reasons. Some of it was never contacted by the injected water, which bypassed it through high-permeability layers, fingered through it because the water was more mobile than the oil, or never reached it between wells — a failure of macroscopic (sweep) efficiency. The rest was contacted but trapped as isolated ganglia in the pores by capillary forces — the residual oil saturation, a failure of microscopic displacement efficiency. EOR is the injection of something the reservoir did not originally contain — chemicals, miscible gases, heat, microbes, or water of altered chemistry — to attack one or both.

The mobility ratio is M = λ_displacing/λ_displaced = (k_rw/μ_w)/(k_ro/μ_o) for a waterflood, with the water relative permeability taken at residual oil (behind the front) and the oil relative permeability at connate water (ahead of it). M ≤ 1 is favourable: the front is stable and sweep is good. M > 1 is unfavourable: the more mobile water fingers through the oil, breakthrough is early and sweep poor. The capillary number N_c = vμ/σ, the ratio of viscous to capillary forces (v the Darcy velocity, μ the displacing-fluid viscosity, σ the interfacial tension), is about 10⁻⁷ to 10⁻⁶ in a waterflood; residual oil only begins to fall when N_c is raised by several orders of magnitude, which in practice means cutting the interfacial tension by a factor of a thousand or more with surfactants or eliminating it altogether by miscibility.

🎯 Two numbers, two jobs
Polymer thickens the water and lowers M, so it improves sweep but leaves the residual saturation in swept pores almost unchanged. Surfactant cuts σ and raises N_c, so it mobilises trapped oil in the pores it reaches but does nothing for the pores it bypasses. That is why chemical floods combine the two, with a polymer drive behind a surfactant slug.

2. Pattern flooding, recovery efficiency, heterogeneity, and macroscopic and microscopic displacement efficiency

Injection and production wells are laid out in repeating patterns. In a five-spot, each producer is surrounded by four injectors at the corners of a square and the ratio of injectors to producers is 1:1; in the normal seven-spot it is 2:1 and in the normal nine-spot 3:1 (the inverted patterns reverse the roles); line drives place rows of injectors opposite rows of producers, directly or staggered. Peripheral and crestal injection suit dipping reservoirs. The overall recovery efficiency of a displacement is the product E = E_D × E_V, and the volumetric sweep is itself E_V = E_A × E_I: areal sweep E_A (the fraction of the pattern area contacted, which falls as M rises and is read from correlations against M), vertical sweep E_I (the fraction of the thickness contacted, which falls with layering and gravity override), and microscopic displacement efficiency E_D = (S_oi − S_or)/S_oi within the contacted rock, where S_oi is the oil saturation at the start of the flood.

Permeability heterogeneity is the main enemy of vertical sweep. The Dykstra-Parsons coefficient V = (k₅₀ − k₈₄.₁)/k₅₀, from a log-probability plot of the permeability distribution (k₅₀ the median and k₈₄.₁ the value exceeded by 84.1% of the samples, one standard deviation below the median), runs from 0 for a homogeneous reservoir toward 1 for an extremely heterogeneous one; the Lorenz coefficient measures the same thing from a plot of cumulative flow capacity against cumulative storage capacity. High-permeability streaks take the injected fluid and water out early, which is why conformance control (gels, polymer, selective completion) is part of EOR.

Where the oil goes in a flood
FactorMeasuresImproved by
E_D, microscopic displacementOil removed from the pores actually contactedRaising N_c: surfactant, alkali, miscibility, heat (lower oil viscosity)
E_A, areal sweepFraction of the pattern area contactedLowering M: polymer, heating the oil; pattern choice
E_I, vertical sweepFraction of the thickness contactedConformance control, lower M, controlling gravity override

3. Screening, and chemical and miscible flooding

Screening matches a process to a reservoir before any detailed study, using the properties that make each process work or fail. Thermal methods suit heavy, viscous oils (whose viscosity heat reduces dramatically), in shallow, thick, permeable sands — depth brings heat loss from the wellbore and high steam pressure. Miscible gas methods suit light oils at reservoir pressures high enough to reach the minimum miscibility pressure (MMP), which usually means depth. Chemical methods suit moderate temperature and salinity (surfactants and polymers degrade in hot, hard brine), sandstones more than clay- or anhydrite-rich carbonates (adsorption and precipitation), and oils of low to moderate viscosity. Microbial methods need temperatures and salinities microbes survive. Screening narrows the options; laboratory core floods, pilots and simulation decide.

Chemical flooding. Polymer flooding (partially hydrolysed polyacrylamide, or the biopolymer xanthan) raises water viscosity and, for polyacrylamide, lowers water permeability, reducing M and improving sweep. Surfactant (micellar) flooding injects a slug that lowers oil-water interfacial tension to ultra-low values, raising N_c and mobilising residual oil into an oil bank; it is followed by a polymer drive for mobility control. Alkaline flooding generates surfactant in situ by reacting with acidic components of the crude, and ASP (alkali-surfactant-polymer) combines all three. Losses by adsorption on rock, and incompatibility with divalent ions, are the chief economic risks. Miscible flooding injects a solvent that mixes with the oil in all proportions, eliminating the interface and so the capillary trapping: first-contact miscibility with solvents such as LPG slugs, and multiple-contact (dynamic) miscibility with CO₂, rich or lean hydrocarbon gas or nitrogen, developed by vaporising oil components into the gas or condensing gas components into the oil above the MMP. CO₂ also swells the oil and lowers its viscosity. Gas is far more mobile than oil, so water-alternating-gas (WAG) injection is used to control mobility and gravity override.

4. Thermal recovery, microbial EOR and low-salinity water flooding

Heat lowers the viscosity of heavy oil by orders of magnitude, and that is the main mechanism of every thermal method, with steam distillation of light ends and thermal expansion adding to it. Cyclic steam stimulation ("huff and puff") injects steam into a well for days to weeks, shuts it in to soak so that the heat spreads, then produces the heated oil from the same well, repeating the cycle as response declines; it is cheap and quick but recovers a modest fraction. Steam flooding injects continuously at injectors and drives heated oil to producers, recovering much more, with steam override and heat losses to cap and base rock as its limits. Hot-water flooding is simpler but carries far less heat per unit mass than steam, whose latent heat dominates. In-situ combustion (fire flooding) injects air and burns a small fraction of the oil — the heavy coke-like residue — in a combustion front that moves through the reservoir, generating heat, steam and gases in place: forward combustion moves with the air, wet combustion adds water to carry heat forward from the burned zone, and reverse combustion moves against the air flow. It has the least surface heat loss and the hardest control.

Microbial EOR (MEOR) injects microbes and nutrients, or stimulates the indigenous population, so that their metabolic products help recovery: biosurfactants lower interfacial tension, gases (CO₂, methane) swell the oil and repressurise, acids and solvents dissolve carbonate and reduce viscosity, and biomass and biopolymers plug high-permeability thief zones to divert flow. It is cheap but slow and hard to control, and limited to temperatures, salinities and pressures that the organisms tolerate. Low-salinity water flooding injects water of much lower salinity (and often altered ionic composition) than the formation brine. Laboratory and field results show extra recovery where the rock contains clays and the oil contains polar components; the proposed mechanisms include wettability alteration toward more water-wet through multi-component ion exchange and expansion of the electrical double layer, and fines migration that diverts flow. It is attractive because it needs no chemicals, but the response is reservoir-specific.

EOR methods at a glance
MethodMain mechanismBest suited to
PolymerLowers mobility ratio, improves sweepModerately viscous oil, heterogeneous sands, moderate temperature
Surfactant / ASPUltra-low IFT raises capillary numberSandstones, low-to-moderate salinity and temperature
CO₂ and hydrocarbon miscibleMiscibility removes capillary trapping; swelling, viscosity cutLight oil, pressure above MMP
Steam (cyclic or flood)Heat reduces oil viscosityHeavy oil, shallow thick permeable sands
In-situ combustionHeat generated in place by burning residueHeavy oil, deeper than steam can reach economically
MicrobialBiosurfactants, gas, acids, selective pluggingTemperature and salinity the microbes tolerate
Low-salinity waterWettability shift toward water-wetClay-bearing sandstones with polar oil components

Key takeaways

  • Oil is left bypassed (sweep) or trapped (capillary); E = E_D × E_A × E_I, with E_D = (S_oi − S_or)/S_oi.
  • M = (k_rw/μ_w)/(k_ro/μ_o), favourable at M ≤ 1; N_c = vμ/σ must rise by orders of magnitude to cut residual oil.
  • Five-spot 1:1, normal seven-spot 2:1, normal nine-spot 3:1; Dykstra-Parsons V = (k₅₀ − k₈₄.₁)/k₅₀ measures heterogeneity.
  • Screen: thermal for heavy shallow oil, miscible gas for light oil above MMP, chemicals for moderate temperature and salinity; polymer fixes sweep, surfactant fixes trapping.
  • Cyclic steam injects, soaks and produces from one well; steam flooding drives oil between wells; in-situ combustion burns residue in place; MEOR and low-salinity water work through biology and wettability.

Practice questions (12)

Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.

  1. In a waterflood, k_rw at residual oil is 0.3 and k_ro at connate water is 0.9. The water viscosity is 0.5 cP and the oil viscosity 5 cP. The end-point mobility ratio is ______ (to two decimal places).

    Numerical answer — type the value.

    Show answer

    Answer: 3.33

    M = (k_rw/μ_w)/(k_ro/μ_o) = (0.3/0.5)/(0.9/5) = 0.6/0.18 = 3.33. Being above 1 it is unfavourable: the water fingers through the oil and breaks through early. Check the other way: M = (k_rw/k_ro)(μ_o/μ_w) = (1/3) × 10 = 3.33.
  2. For the same waterflood (k_rw = 0.3, k_ro = 0.9, μ_o = 5 cP), polymer is added so that the mobility ratio becomes exactly 1, assuming it changes only the water viscosity. The required viscosity of the polymer solution is ______ cP (to two decimal places).

    Numerical answer — type the value.

    Show answer

    Answer: 1.67

    M = 1 means k_rw/μ_p = k_ro/μ_o, so μ_p = k_rw μ_o/k_ro = 0.3 × 5/0.9 = 1.5/0.9 = 1.667 cP, which is 1.67. The polymer must make the water about 3.3 times more viscous, matching the factor by which M exceeded 1.
  3. A core flood starts at an oil saturation of 0.70 and ends at a residual oil saturation of 0.25. The microscopic displacement efficiency is ______ (to two decimal places).

    Numerical answer — type the value.

    Show answer

    Answer: 0.64

    E_D = (S_oi − S_or)/S_oi = (0.70 − 0.25)/0.70 = 0.45/0.70 = 0.643, which is 0.64. This assumes the formation volume factor is the same at the start and end, which holds for a waterflood above the bubble point.
  4. In a waterflood the microscopic displacement efficiency is 0.65, the areal sweep efficiency 0.70 and the vertical sweep efficiency 0.80. The overall recovery efficiency is ______ (to two decimal places).

    Numerical answer — type the value.

    Show answer

    Answer: 0.36

    E = E_D × E_A × E_I = 0.65 × 0.70 × 0.80. E_A × E_I = 0.56 (the volumetric sweep), and 0.65 × 0.56 = 0.364, which is 0.36. Each factor below one multiplies the loss.
  5. A reservoir held 50 million STB of oil originally. Primary recovery and waterflooding have produced 17.5 million STB, and a chemical flood adds a further 4 million STB. The overall recovery factor is ______ %.

    Numerical answer — type the value.

    Show answer

    Answer: 43

    RF = cumulative recovery/OOIP = (17.5 + 4)/50 = 21.5/50 = 0.43 = 43%. The waterflood alone reached 17.5/50 = 35%, so the EOR increment is 8 percentage points of the original oil in place.
  6. A surfactant lowers the oil-water interfacial tension from 30 mN/m to 0.003 mN/m while velocity and viscosity stay the same. The capillary number increases by a factor of ______.

    Numerical answer — type the value.

    Show answer

    Answer: 10000

    N_c = vμ/σ, so at constant v and μ it scales as 1/σ: 30/0.003 = 10 000. Four orders of magnitude is the kind of increase needed before residual oil starts to be mobilised, which is why IFT reduction is the core of surfactant flooding.
  7. On a log-probability plot of core permeabilities, the median permeability is 100 md and the permeability at 84.1% cumulative probability (samples exceeding it) is 30 md. The Dykstra-Parsons coefficient is ______ (to one decimal place).

    Numerical answer — type the value.

    Show answer

    Answer: 0.7

    V = (k₅₀ − k₈₄.₁)/k₅₀ = (100 − 30)/100 = 0.7 — a heterogeneous reservoir (a homogeneous one gives 0), in which high-permeability layers will take a disproportionate share of the injected fluid and vertical sweep will suffer.
  8. In a regular five-spot waterflood pattern, the ratio of injection wells to production wells is

    1. 1:1
    2. 2:1
    3. 3:1
    4. 1:4
    Show answer

    Answer: A — 1:1

    Each producer has four injectors at the corners, but each injector is shared by four patterns, so over a large field there is one injector per producer. The normal seven-spot is 2:1 and the normal nine-spot 3:1; 1:4 counts corners without sharing.
  9. A shallow, thick, high-permeability sand contains a heavy oil of very high viscosity. The EOR process most likely to pass screening is

    1. steam flooding or cyclic steam stimulation
    2. CO₂ miscible flooding
    3. nitrogen injection
    4. surfactant flooding without polymer
    Show answer

    Answer: A — steam flooding or cyclic steam stimulation

    Heat reduces heavy-oil viscosity by orders of magnitude, and shallow depth keeps wellbore heat loss and steam pressure manageable. Miscible gas needs a light oil at pressure above the MMP, and a surfactant slug without mobility control would finger badly through a very viscous oil.
  10. Which statements about miscible gas flooding are correct? (More than one option may be correct.)

    1. CO₂ can develop multiple-contact miscibility with a light oil above the minimum miscibility pressure
    2. Miscibility eliminates the interface and hence the capillary trapping of residual oil
    3. Water-alternating-gas injection is used to control the adverse mobility of the gas
    4. Miscible flooding works best in shallow reservoirs of very heavy oil
    Show answer

    Answer: A — CO₂ can develop multiple-contact miscibility with a light oil above the minimum miscibility pressure; B — Miscibility eliminates the interface and hence the capillary trapping of residual oil; C — Water-alternating-gas injection is used to control the adverse mobility of the gas

    Above the MMP, CO₂ and a light oil exchange components until they become miscible; with no interface there is no capillary pressure to trap oil; gas is much more mobile than oil, so WAG slugs of water restrain it. Heavy oil and shallow depth are the conditions for thermal methods, not miscible ones.
  11. In cyclic steam stimulation, the sequence of operations at a single well is

    1. inject steam, shut in to soak, then produce, and repeat
    2. produce, inject air, ignite, then produce again
    3. inject polymer, then surfactant, then water
    4. inject steam continuously while an offset well produces
    Show answer

    Answer: A — inject steam, shut in to soak, then produce, and repeat

    "Huff and puff" uses one well for everything: a steam slug heats the near-well zone, a soak lets the heat spread and condense, and the same well then produces the thinned oil until the rate falls and the cycle is repeated. Continuous injection with offset producers is steam flooding, and air injection with ignition is in-situ combustion.
  12. Which of the following are mechanisms by which microbial EOR or low-salinity water flooding can increase oil recovery? (More than one option may be correct.)

    1. Production of biosurfactants that lower interfacial tension
    2. Selective plugging of high-permeability zones by biomass
    3. Alteration of wettability toward more water-wet conditions
    4. Raising the reservoir temperature by several hundred degrees
    Show answer

    Answer: A — Production of biosurfactants that lower interfacial tension; B — Selective plugging of high-permeability zones by biomass; C — Alteration of wettability toward more water-wet conditions

    Microbes can make surfactants, gases, acids and biomass; the biomass diverts flow from thief zones. Low-salinity water is thought to shift wettability toward water-wet through ion exchange and double-layer expansion. Neither process adds significant heat — that is the thermal methods’ mechanism.